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13x^2-169x=0
a = 13; b = -169; c = 0;
Δ = b2-4ac
Δ = -1692-4·13·0
Δ = 28561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28561}=169$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-169)-169}{2*13}=\frac{0}{26} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-169)+169}{2*13}=\frac{338}{26} =13 $
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